ENGINEERING AND SCIENCE ADMISSIONS TEST PREPARATION
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Question 10

In the time period given, source X undergoes five half-lives and source Y undergoes three. The activity is proportional to the number of nuclei present so the activity of source X goes down by a factor of 32 and source Y by a factor of 8.
$\frac{320}{32}=10$
$\frac{480}{8}=60$
$10+60=70Bq$
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  • Home
  • Tutor profile
  • Solutions
  • eBook
  • ESAT Tuition
  • Contact
  • Time saving
  • Speed hints
  • Testimonials/Statistics
  • Specimen solutions
  • 2016 Solutions
  • 2017 Solutions
  • 2018 Solutions
  • 2019 Solutions
  • 2020 Solutions
  • 2021 Solutions
  • 2022 Solutions
  • 2023 Solutions
  • New Specimen Solutions
  • NSAA Specimen Section 2 solutions
  • NSAA 2016 Section 2 Solutions
  • NSAA 2017 Section 2 Solutions
  • PAT Tuition
  • Physics Aptitude Test Mock Papers
  • MAT Tuition
  • Maths Challenge and BMO Tuition
  • Advance Preparation Programme
  • Maths enrichment tuition
  • Maths for Economics Degrees Tuition
  • GDPR and data protection
  • Boiler