Question 17
$New P=\frac{K}{(1.4)^{2}Q^{2}}=\frac{P}{1.96}$
Division by 1.96 returns an answer just over half the original value.
$New P=\frac{K}{(1.4)^{2}Q^{2}}=\frac{P}{1.96}$
Division by 1.96 returns an answer just over half the original value.