Question 23
$x^{2}+2x-8\geq 0$
$(x+4)(x-2)\geq 0$
If $x\geq 2$ then both brackets are positive and the inequality is satisfied.
If $x\leq -4$ then both brackets are negative and the inequality is satisfied.
$x^{2}+2x-8\geq 0$
$(x+4)(x-2)\geq 0$
If $x\geq 2$ then both brackets are positive and the inequality is satisfied.
If $x\leq -4$ then both brackets are negative and the inequality is satisfied.