Question 3
Writing the area of the triangle using first QR as the base, followed by PR we have:
$\frac{1}{2}\times10\times20=\frac{1}{2}\times PR \times x$
Where $x$ is the shortest distance from the hypotenuse to Q.
By Pythagoras' Theorem, $PR=10\sqrt5$ so $x=\frac{20}{\sqrt5}=4\sqrt5$.
Writing the area of the triangle using first QR as the base, followed by PR we have:
$\frac{1}{2}\times10\times20=\frac{1}{2}\times PR \times x$
Where $x$ is the shortest distance from the hypotenuse to Q.
By Pythagoras' Theorem, $PR=10\sqrt5$ so $x=\frac{20}{\sqrt5}=4\sqrt5$.