ENGINEERING ADMISSIONS ASSESSMENT PREPARATION
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Question 3

Writing the area of the triangle using first QR as the base, followed by PR we have:

$\frac{1}{2}\times10\times20=\frac{1}{2}\times PR \times x$

Where $x$ is the shortest distance from the hypotenuse to Q.

By Pythagoras' Theorem, $PR=10\sqrt5$ so $x=\frac{20}{\sqrt5}=4\sqrt5$.
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  • Home
  • Tutor profile
  • Solutions
  • eBook
  • Tuition
  • Courses
  • Contact
  • Time saving
  • Speed hints
  • Testimonials/Statistics
  • Specimen solutions
  • 2016 Solutions
  • 2017 Solutions
  • 2018 Solutions
  • 2019 Solutions
  • 2020 Solutions
  • 2021 Solutions
  • New Specimen Solutions
  • NSAA Specimen Section 2 solutions
  • NSAA 2016 Section 2 Solutions
  • NSAA 2017 Section 2 Solutions
  • NSAA Tuition and eBook
  • PAT Tuition
  • Physics Aptitude Test Mock Papers
  • MAT Tuition
  • STEP Tuition
  • Maths Challenge and BMO Tuition
  • Advance Preparation Programme
  • Physics Degree Tuition
  • Maths enrichment tuition
  • Maths for Economics Degrees Tuition
  • GDPR and data protection
  • Boiler